Physics System of Particles Rotational Motion Conservation of Angular Momentum (Combined Translation & Rotational Motion) MCQ (Single Correct)

A disc of mass M and radius R is rolling with angular speed ω on a horizontal plane as shown. The magnitude of angular momentum of the disc about the origin O is

A
(1/2)MR 2 ω
B
MR 2 ω
C
(3/2)MR 2 ω
D
2MR 2 ω

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Text Solution

Verified by Experts
The correct answer is:
C

From the theorem –

.......

We may write

Angular momentum about O = Angular momentum about COM + Angular momentum of COM about origin

∴ L 0 = I ω + MRV

= MR 2 ω + MR(R ω )

= MR 2 ω

Note that in this case both the terms in equation i.e. and M have the same direction . That is why we have used L 0 = I ω + MRV. We will use L 0 = I ω ~ MRV if they are in opposite directions shown in figure .

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